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Home > News & Articles > The Value of g: Definitions, Examples, History, Importance, How to Calculate, Planets and their Masses
Updated on 08th June, 2023 , 5 min read
It is vital to remember that the value of g does not remain constant throughout the cosmos. The acceleration due to gravity on various celestial bodies, such as the Moon or Mars, differs from the value on Earth. On Earth, the value of g can also fluctuate somewhat due to factors such as height and local geology. Higher elevations have a significantly lower gravitational force, resulting in a slightly smaller value of g. Furthermore, changes in the density and distribution of rocks and minerals under the Earth's surface can cause minor regional differences in gravitational acceleration. When constructing structures, vehicles, and equipment that must endure gravitational forces, engineers consider the value of g. Furthermore, a correct understanding of g aids in the study of the Earth's internal structure and the monitoring of geological activity in subjects such as geophysics, seismology, and geodesy.
Also Read: Value of e
The value of g reflects the acceleration caused by gravity on the Earth's surface. It's around 9.8 meters per second squared (m/s²). This indicates that an object's velocity increases by 9.8 m/s for every second it is in free fall near the Earth's surface.
Henry Cavendish made the first direct measurement of the gravitational pull between two bodies in a laboratory setting 71 years after Newton passed away in 1798. Cavendish had figured out how the angle of rotation and torsional force related to one another.
History of the Value of g
The net acceleration that objects experience as a result of the combined action of gravity and centrifugal force as a result of the Earth's rotation is known as Earth's gravity, abbreviated as g. It is a vector quantity whose strength or magnitude is determined by the norm. This acceleration is represented in newtons per kilogram (N/kg or Nkg¹), which is equivalent to meters per second squared (m/s² or ms²) in SI units. When air resistance is ignored, the acceleration of gravity at Earth's surface is roughly 9.81 m/s² (32.2 ft/s²), which implies that the speed of an item falling freely will rise by 9.81 m (32.2 ft) per second.
Earth's acceleration caused by gravity, or the magnitude of g, is 9.8 m/s². According to this, an item falling freely on Earth would accelerate by 9.8 meters per second. The gravity of the Earth is to blame for this acceleration.
Consider the following example for the value of g- An object is dropped from a height of 20 meters above the earth. The value of g may be used to compute the time it takes the item to reach the ground and its ultimate velocity upon contact.
Given,
Initial height (h) = 20 m
Gravity due to acceleration (g) = 9.8 m/s²
To get the time taken (t), apply the equation-
Where,
h is the height
g is the gravity acceleration
t is the time taken.
When we rearrange the equation to solve for time (t),
We get,
By putting values,
t = sqrt (2*20 / 9.8)
= 2.02 seconds
So, under the effect of gravity, the object would descend from a height of 20 meters to the earth in roughly 2.02 seconds.
We may apply the equation,
v = g * t to get the final velocity (v) upon contact
Where,
v is the velocity
t is the time taken
By putting values,
v = 9.8 * 2.02
= 19.80 m/s
As a result, right before impacting the earth, the item would attain a velocity of around 19.80 meters per second. In this example, we used the value of "g" (9.8 m/s²) to calculate the time it took the item to descend and the ultimate velocity it would acquire owing to gravity.
The magnitude of g changes depending on the size of the body. Below is a comprehensive table of planets and their masses, radii, and g-factors.
|
Planet/Satellite |
Mass (kg) |
Radius (m) |
Value of g (m/s²) |
|
Earth |
6 × 10²â´ |
6.4 × 10ⶠ|
9.8 |
|
Jupiter |
1.901 × 10²â· |
6.98 × 10â· |
26.0 |
|
Mars |
6.42 × 10²³ |
3.38 × 10ⶠ|
3.75 |
|
Mercury |
3.2 × 10²³ |
2.43 × 10ⶠ|
3.61 |
|
Neptune |
1.03 × 10²â¶ |
2.27 × 10â· |
13.3 |
|
Pluto |
1.2 × 10²² |
1.15 × 10ⶠ|
0.61 |
|
Saturn |
5.68 × 10²â¶ |
5.82 × 10â· |
11.2 |
|
Uranus |
8.68 × 10²âµ |
2.35 × 10â· |
10.5 |
|
Venus |
4.88 × 10²4 |
6.073 × 10ⶠ|
8.83 |
The value of "g" is essential for understanding object motion, computing forces, and forecasting trajectories. It has far-reaching ramifications in many scientific and technical disciplines, including physics, astronomy, geophysics, and structural engineering. A precise understanding of "g" enables precise calculations and designs involving gravitational forces and the behavior of objects near the Earth's surface.
The formula for the acceleration caused by gravity-
Where,
The value of G, or the gravitational constant, is 6.674 x 10⻹¹m³kg⻹s⻲.
The enormous body's mass, M, is expressed in kilograms.
The huge body's radius, R, is calculated using the unit m.
Using m/s², gravity's acceleration, or g, is determined.
The Earth has a mass of 6 x 10²â´ kg.
The earth's radius is 6.4 x 10ⶠmeters.
When we change the values in the formula, we obtain-
Consequently,
g = 9.8m/s² is the value of g on Earth.
The unit of acceleration is followed by the acceleration caused by gravity.
The acceleration of gravity is a vector quantity that has both direction and magnitude. Gravity would aim directly toward the center of a spherically symmetric Earth. As a result of the Earth's slightly flatter shape, there are noticeable variations in the direction of gravity, namely the separation between geodetic latitude and geocentric latitude. Local mass anomalies like mountains can generate vertical deflection, a smaller deviation.
In summary, g indicates the acceleration due to gravity on the Earth's surface and is roughly 9.8 m/s². It is a basic constant that affects the behavior of objects near the Earth's surface and has important consequences for a wide range of scientific and practical applications.
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By - Nikita Parmar 2023-08-25 09:48:44 , 11 min readAns. The typical value of "g" on Earth’s surface is around 9.8 meters per second squared (m/s²). This figure shows the average gravitational acceleration experienced by objects close to the Earth’s surface.
Ans. Henry Cavendish made the first direct measurement of the gravitational pull between two bodies in a laboratory setting 71 years after Newton passed away in 1798. Cavendish had figured out how the angle of rotation and torsional force related to one another.
Ans. The value of "g" may be determined using a variety of experimental techniques. A pendulum may be used to measure the time period of its oscillation, which is a frequent approach. Another way includes the use of devices such as gravimeters or accelerometers, which directly detect gravity’s acceleration.
Ans. At the Earth’s poles, ans. g is the largest.
Ans. The value of "g" reflects the acceleration caused by gravity on the Earth’s surface. It measures the rate of acceleration of objects in free fall near the Earth’s surface.
Ans. The value of "g" is essential for understanding object motion, computing forces, and forecasting trajectories. It has far-reaching ramifications in many scientific and technical disciplines, including physics, astronomy, geophysics, and structural engineering. A precise understanding of "g" enables precise calculations and designs involving gravitational forces and the behavior of objects near the Earth’s surface.
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